3.10.14 \(\int \frac {1}{\sqrt {c x^2} (a+b x)^2} \, dx\) [914]

Optimal. Leaf size=59 \[ \frac {x}{a \sqrt {c x^2} (a+b x)}+\frac {x \log (x)}{a^2 \sqrt {c x^2}}-\frac {x \log (a+b x)}{a^2 \sqrt {c x^2}} \]

[Out]

x/a/(b*x+a)/(c*x^2)^(1/2)+x*ln(x)/a^2/(c*x^2)^(1/2)-x*ln(b*x+a)/a^2/(c*x^2)^(1/2)

________________________________________________________________________________________

Rubi [A]
time = 0.01, antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {15, 46} \begin {gather*} -\frac {x \log (a+b x)}{a^2 \sqrt {c x^2}}+\frac {x \log (x)}{a^2 \sqrt {c x^2}}+\frac {x}{a \sqrt {c x^2} (a+b x)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(Sqrt[c*x^2]*(a + b*x)^2),x]

[Out]

x/(a*Sqrt[c*x^2]*(a + b*x)) + (x*Log[x])/(a^2*Sqrt[c*x^2]) - (x*Log[a + b*x])/(a^2*Sqrt[c*x^2])

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[a^IntPart[m]*((a*x^n)^FracPart[m]/x^(n*FracPart[m])), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 46

Int[((a_) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x
)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && Lt
Q[m + n + 2, 0])

Rubi steps

\begin {align*} \int \frac {1}{\sqrt {c x^2} (a+b x)^2} \, dx &=\frac {x \int \frac {1}{x (a+b x)^2} \, dx}{\sqrt {c x^2}}\\ &=\frac {x \int \left (\frac {1}{a^2 x}-\frac {b}{a (a+b x)^2}-\frac {b}{a^2 (a+b x)}\right ) \, dx}{\sqrt {c x^2}}\\ &=\frac {x}{a \sqrt {c x^2} (a+b x)}+\frac {x \log (x)}{a^2 \sqrt {c x^2}}-\frac {x \log (a+b x)}{a^2 \sqrt {c x^2}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]
time = 0.00, size = 44, normalized size = 0.75 \begin {gather*} \frac {x (a+(a+b x) \log (x)-(a+b x) \log (a+b x))}{a^2 \sqrt {c x^2} (a+b x)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(Sqrt[c*x^2]*(a + b*x)^2),x]

[Out]

(x*(a + (a + b*x)*Log[x] - (a + b*x)*Log[a + b*x]))/(a^2*Sqrt[c*x^2]*(a + b*x))

________________________________________________________________________________________

Mathics [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {cought exception: maximum recursion depth exceeded while calling a Python object} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

mathics('Integrate[1/(Sqrt[c*x^2]*(a + b*x)^2),x]')

[Out]

cought exception: maximum recursion depth exceeded while calling a Python object

________________________________________________________________________________________

Maple [A]
time = 0.13, size = 50, normalized size = 0.85

method	result	size
default	\(\frac {x \left (b x \ln \left (x \right )-b \ln \left (b x +a \right ) x +a \ln \left (x \right )-a \ln \left (b x +a \right )+a \right )}{\sqrt {c \,x^{2}}\, a^{2} \left (b x +a \right )}\)	\(50\)
risch	\(\frac {x}{a \left (b x +a \right ) \sqrt {c \,x^{2}}}+\frac {x \ln \left (-x \right )}{\sqrt {c \,x^{2}}\, a^{2}}-\frac {x \ln \left (b x +a \right )}{a^{2} \sqrt {c \,x^{2}}}\)	\(56\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x+a)^2/(c*x^2)^(1/2),x,method=_RETURNVERBOSE)

[Out]

x*(b*x*ln(x)-b*ln(b*x+a)*x+a*ln(x)-a*ln(b*x+a)+a)/(c*x^2)^(1/2)/a^2/(b*x+a)

________________________________________________________________________________________

Maxima [A]
time = 0.27, size = 61, normalized size = 1.03 \begin {gather*} -\frac {\sqrt {c x^{2}} b}{a^{2} b c x + a^{3} c} - \frac {\left (-1\right )^{\frac {2 \, a c x}{b}} \log \left (-\frac {2 \, a c x}{b {\left | b x + a \right |}}\right )}{a^{2} \sqrt {c}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a)^2/(c*x^2)^(1/2),x, algorithm="maxima")

[Out]

-sqrt(c*x^2)*b/(a^2*b*c*x + a^3*c) - (-1)^(2*a*c*x/b)*log(-2*a*c*x/(b*abs(b*x + a)))/(a^2*sqrt(c))

________________________________________________________________________________________

Fricas [A]
time = 0.31, size = 44, normalized size = 0.75 \begin {gather*} \frac {\sqrt {c x^{2}} {\left ({\left (b x + a\right )} \log \left (\frac {x}{b x + a}\right ) + a\right )}}{a^{2} b c x^{2} + a^{3} c x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a)^2/(c*x^2)^(1/2),x, algorithm="fricas")

[Out]

sqrt(c*x^2)*((b*x + a)*log(x/(b*x + a)) + a)/(a^2*b*c*x^2 + a^3*c*x)

________________________________________________________________________________________

Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\sqrt {c x^{2}} \left (a + b x\right )^{2}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a)**2/(c*x**2)**(1/2),x)

[Out]

Integral(1/(sqrt(c*x**2)*(a + b*x)**2), x)

________________________________________________________________________________________

Giac [F] N/A
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Limit: Max order reached or unable to make series expansion Error: Bad Argument Value} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x+a)^2/(c*x^2)^(1/2),x)

[Out]

Limit: Max order reached or unable to make series expansion Error: Bad Argument Value

________________________________________________________________________________________

Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {1}{\sqrt {c\,x^2}\,{\left (a+b\,x\right )}^2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((c*x^2)^(1/2)*(a + b*x)^2),x)

[Out]

int(1/((c*x^2)^(1/2)*(a + b*x)^2), x)

________________________________________________________________________________________